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Sonntag Nachmittagsturnier  Sonntag 13.04.2025    
 

Ergebnis | Persönliche Scores

1 2025-04-13  So - Clubturnier
MARTIN Ingeborg - WINKLER Herbert
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Paar: 1    MARTIN Ingeborg - WINKLER Herbert

Score: 53,000    44,167 %    Platz: 5    
                    
Rnd  Tisch  Als  Geg  Board  Kont      Aus  Ergebnis  Score    %     Runde    %       Ges        %        Name d. Gegners

 1     1    O-W   6     1    6H   W  = T4       -980  4,000  100                                          FOSTEL - RIEDL
                        2    2P   O -1 K6     50      2,000   50                                            
                        3    6N   W -2 H10   200      0,000    0                                            
                        4    4P   W -1 KK    100      1,000   25                                            
                        5    4H   W  = KK       -420  1,000   25                                            
                        6    1N   O  = K5        -90  3,000   75    11,000   46    11,000   45,833          

 2     2    N-S   3     19   4H   S +1 PA    450      4,000  100                                          BAMMER - KOLLER
                        20   2H   O  = KA       -110  2,000   50                                            
                        21   5K   O -1 P9     50      0,000    0                                            
                        22   4K   N  = HA    130      3,000   75                                            
                        23   Pass              0      2,000   50                                            
                        24   3N   O -1 K8     50      3,000   75    14,000   58    25,000   52,083          

 3     3    N-S   5     7    3T   N -1 KA       -100  2,000   50                                          LUSTIG - MAGYAR
                        8    2N   N  = KA    120      4,000  100                                            
                        9    4Px  W -1 HK    200      0,000    0                                            
                        10   3N   W +1 K3       -630  0,000    0                                            
                        11   3N   W +2 T2       -460  4,000  100                                            
                        12   3P   W  = K2       -140  2,000   50    12,000   50    37,000   51,389          

 4     3    O-W   2     13   5T   N  = H2    600      4,000  100                                          WASSER - HOCHSTÖGER
                        14   3T   O +1 PA       -130  3,000   75                                            
                        15   2P   S +1 H4    140      0,000    0                                            
                        16   4H   W  = TA       -620  0,000    0                                            
                        17   4P   N -1 T8        -50  3,000   75                                            
                        18   1N   S  = T8     90      1,000   25    11,000   46    48,000   50,000          

 5     2    O-W   4     25   3P   O -1 K3    100      0,000    0                                          PAPRSEK - WIMMER
                        26   1N   O +1 K3       -120  4,000  100                                            
                        27   2P   S +3 K10   200      0,000    0                                            
                        28   2Hx  S  = PA    670      0,000    0                                            
                        29   4H   O -1 PK    100      0,000    0                                            
                        30   4P   N  = HD    420      1,000   25     5,000   21    53,000   44,167          

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